In the previous section, we saw some solved examples related to properties of determinants. In this section, we will see area of triangles.
Some basics can be written in 3 steps:
1. In our earlier coordinate geometry classes, we have seen an expression to find the area of any triangle:
$\text{Area} = \frac{1}{2} |x_1(y_2 - y_3) + x_2(y_3 - y_1) + x_3(y_1 - y_2)|$
(Details here)
2. Now consider the determinant:
$\Delta = \frac{1}{2} \left|\begin{array}{r}
x_1 &{ y_1 } &{ 1 } \\
x_2 &{ y_2 } &{ 1 } \\
x_3 &{ y_3 } &{ 1 } \\
\end{array}\right|$
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If we expand this determinant along the first column, we will get the same expression as in (1).
3. That means, area of a triangle can be written in "determinant form" also.
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But it is important to take the absolute value of the determinant. This is because, area cannot be a negative quantity.
Now we will see some solved examples.
Solved example 20.13
Find the area of the triangle whose vertices are (-1.5,2), (-2.5,-2), (4,1.5)
Solution:
◼ Remarks:
• 3: Here we apply two operations:
♦ R1 → R1 − R3.
♦ R2 → R2 − R3.
4: Here we expand the determinant along C3.
Solved example 20.14
Find the equation of the line joining A(1,3) and B(0,0) using determinants and find k if D(k,0) is a point such that area of triangle ABD is 3 sq units.
Solution:
Part (i):
1. Let P(x,y) be any point on the line AB.
Then area of the triangle APB = 0. This is because, three collinear points cannot form a triangle.
2. So we can write:
◼ Remarks:
• 2 (magenta color): Here we expand the determinant along the second row.
• 3 (magenta color): Here we use the index (2+3). This is because, '1' is the a23th element.
3. Since the area is zero, we can write:
-(1/2)(y-3x) = 0
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From this we get: -y + 3x = 0
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Which is same as: y = 3x
4. The line y=3x will pass through both A(1,3) and B(0,0).
Part (ii):
◼ Remarks:
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2 (magenta color): Here we write $\pm 3$ because, the value of the determinant can be either +3 or -3. We can ignore the -ve sign only when we write it as an area.
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3 (magenta color): Here we expand the determinant along the second row.
•
3 (magenta color): Here we use the index (2+3). This is because, '1' is the a23th element.
◼ We can write:
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Area of the triangle formed by the three points A(1,3), B(0,0) and D(2,0) is 3 units.
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Area of the triangle formed by the three points A(1,3), B(0,0) and D(-2,0) is also 3 units.
The link below gives a few more solved examples:
In the next section, we will see Minors and Cofactors.
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