In the previous section, we saw the first property of determinants. In this section, we will see the second property.
Property II
This can be written in 9 steps:
1. Let Δ = $\left |\begin{array}{r}
a_1 &{ a_2 } &{ a_3 } \\
b_1 &{ b_2 } &{ b_3 } \\
c_1 &{ c_2 } &{ c_3 } \\
\end{array}\right | $.
2. We can write a new determinant Δ1 by interchanging any two rows (or columns). For example, by interchanging the second and third rows, we get:
Δ1 = $\left |\begin{array}{r}
a_1 &{ a_2 } &{ a_3 } \\
c_1 &{ c_2 } &{ c_3 } \\
b_1 &{ b_2 } &{ b_3 } \\
\end{array}\right |$.
3. Let us evaluate Δ. We will expand along R1.
4. Let us evaluate Δ1. We will expand along R1.
5. Let us compare Δ and Δ1. Both are written together below:
• Identical terms are given the same number. It is easy to see that, all six terms are identical. But the signs are opposite.
6. Let us compare (−Δ) and Δ1. Both are written together below:
• Identical terms are given the same number. It is easy to see that, all six terms are identical. The signs are also identical.
• So we get: −Δ = Δ1.
7. In the same way, the reader may check the result by interchanging any two columns.
8. Based on the above steps, we can write:
If any two rows (or columns) of a determinant are interchanged, then the sign of the determinant changes.
9. Suppose that:
♦ Ri and Rj represent the ith and jth rows respectively.
♦ Ci and Cj represent the ith and jth columns respectively.
• Then the process of interchanging the two rows can be represented as Ri ↔ Rj.
• Also, the process of interchanging the two columns can be represented as Ci ↔ Cj.
Now we have a clear understanding about property II. Let us see an example. It can be written in 5 steps:
1. Let Δ = $\left |\begin{array}{r}
2 &{ -3 } &{ 5 } \\
6 &{ 0 } &{ 4 } \\
1 &{ 5 } &{ 7 } \\
\end{array}\right | $.
2. Let us do C1 ↔ C3. We get:
Δ1 = $\left |\begin{array}{r}
5 &{ -3 } &{ 2 } \\
4 &{ 0 } &{ 6 } \\
7 &{ 5 } &{ 1 } \\
\end{array}\right |$.
3. Let us evaluate Δ. We will expand along R2.
4. Let us evaluate Δ1. We will expand along C2.
5. Comparing the results in (3) and (4), we see that:
−Δ = Δ1.
In the next section, we will see Property III.
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