Tuesday, April 2, 2024

20.5 - Property III

In the previous section, we saw the second property of determinants. In this section, we will see the third property.

Property III
This can be written in 9 steps:
1. Let Δ = $\left |\begin{array}{r}                           
a_1    &{    a_2    }    &{    a_3    }    \\
b_1    &{    b_2    }    &{    b_3    }    \\
a_1    &{    a_2    }    &{    a_3    }    \\
\end{array}\right | $.
• We see that, R1 and R3 are identical.
2. Let us evaluate Δ. We will expand along R1.

 

◼ Remarks:
• In 3(magenta color),
    ♦ First term = -1 × sixth term 
    ♦ Second term = -1 × fourth term 
    ♦ Third term = -1 × fifth term

• So the sum is zero. 

3. In the same way, the reader may check the result when any two columns are identical. It will be zero.

4. Based on the above steps, we can write:
If any two rows (or columns) of a determinant are identical, then the value of that determinant will be zero.

5. The proof can be written in 6 steps:
(i) Suppose that, two rows of a matrix A are identical.
(ii) Calculate det(A)
(iii) Interchange the identical rows and write a new matrix A1.
(iii) Calculate det(A1)
(iv) Applying property II, we can write: -det(A) = det(A1)
(v) In the matrix A, we interchanged identical rows.
So A = A1
(vi) Since A = A1, the determinants will also be equal.
That is., det(A) = det(A1)
(vii) Substituting the above value of det(A1) into (iv), we get:
-det(A) = det(A)
• This is possible only if det(A) = 0


Now we have a clear understanding about property III. Let us see an example. It can be written in 5 steps:

1. Let Δ = $\left |\begin{array}{r}                           
5    &{    6    }    &{    5    }    \\
-4    &{    3    }    &{   -4    }    \\
1    &{    9    }    &{    1    }    \\
\end{array}\right | $.
2. Let us evaluate Δ. We will expand along R1.


4. In this example, C1 and C3 are identical.


In the next section, we will see Property IV.

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20.4 - Property II

In the previous section, we saw the first property of determinants. In this section, we will see the second property.

Property II
This can be written in 9 steps:
1. Let Δ = $\left |\begin{array}{r}                           
a_1    &{    a_2    }    &{    a_3    }    \\
b_1    &{    b_2    }    &{    b_3    }    \\
c_1    &{    c_2    }    &{    c_3    }    \\
\end{array}\right | $.
2. We can write a new determinant Δ1 by interchanging any two rows (or columns). For example, by interchanging the second and third rows, we get:
Δ1 = $\left |\begin{array}{r}                           
a_1    &{    a_2    }    &{    a_3    }    \\
c_1    &{    c_2    }    &{    c_3    }    \\
b_1    &{    b_2    }    &{    b_3    }    \\
\end{array}\right |$.
3. Let us evaluate Δ. We will expand along R1.

4. Let us evaluate Δ1. We will expand along R1.


5. Let us compare Δ and Δ1. Both are written together below:


• Identical terms are given the same number. It is easy to see that, all six terms are identical. But the signs are opposite.

6. Let us compare (−Δ) and Δ1. Both are written together below:


• Identical terms are given the same number. It is easy to see that, all six terms are identical. The signs are also identical.
• So we get: −Δ = Δ1.

7. In the same way, the reader may check the result by interchanging any two columns.

8. Based on the above steps, we can write:
If any two rows (or columns) of a determinant are interchanged, then the sign of the determinant changes.

9. Suppose that:
    ♦ Ri and Rj represent the ith and jth rows respectively.
    ♦ Ci and Cj represent the ith and jth columns respectively.

• Then the process of interchanging the two rows can be represented as Ri ↔ Rj.
• Also, the process of interchanging the two columns can be represented as Ci ↔ Cj.


Now we have a clear understanding about property II. Let us see an example. It can be written in 5 steps:

1. Let Δ = $\left |\begin{array}{r}                           
2    &{    -3    }    &{    5    }    \\
6    &{    0    }    &{    4    }    \\
1    &{    5    }    &{    7    }    \\
\end{array}\right | $.
2. Let us do C1 ↔ C3. We get:
Δ1 = $\left |\begin{array}{r}                           
5    &{    -3    }    &{    2    }    \\
4    &{    0    }    &{    6    }    \\
7    &{    5    }    &{    1    }    \\
\end{array}\right |$.
3. Let us evaluate Δ. We will expand along R2.


4. Let us evaluate Δ1. We will expand along C2.


5. Comparing the results in (3) and (4), we see that:
−Δ = Δ1

In the next section, we will see Property III.

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Monday, April 1, 2024

20.3 - Property I

In the previous section, we saw how to obtain the determinant of order 3. In this section, we will see some properties of determinants.

• The properties will help us to obtain maximum number of zeroes in a row/column.
• When zeroes are obtained in this way, the evaluation of the determinant will become easier.
• The properties are applicable to determinants of any order. But for our present discussion, we will consider order 3 only.

Property I
This can be written in 8 steps:
1. Let Δ = $\left |\begin{array}{r}                           
a_1    &{    a_2    }    &{    a_3    }    \\
b_1    &{    b_2    }    &{    b_3    }    \\
c_1    &{    c_2    }    &{    c_3    }    \\
\end{array}\right | $.
2. We can write a new determinant Δ1 by interchanging rows and columns. That is.,
Δ1 = $\left |\begin{array}{r}                           
a_1    &{    b_1    }    &{    c_1    }    \\
a_2    &{    b_2    }    &{    c_2    }    \\
a_3    &{    b_3    }    &{    c_3    }    \\
\end{array}\right |$.
3. Let us evaluate Δ. We will expand along R1.

4. Let us evaluate Δ1. We will expand along R1.


5. Let us compare Δ and Δ1. Both are written together below:


• Identical terms are given the same number. It is easy to see that, all six terms are identical. The signs are also identical.
• So we get: Δ = Δ1.

6. Based on the above steps, we can write:
The determinant remains unchanged if it's rows and columns are interchanged.

7. Recall that, transpose of a matrix is obtained by interchanging rows and columns of that matrix. So we can write:
If A is a square matrix, then det(A) = det(A')

8. If Ri and Ci represent the ith row and ith column respectively, then the process of interchanging the rows and columns can be represented as Ri ↔ Ci.


Now we have a clear understanding about property I. Let us see an example. It can be written in 5 steps:

1. Let Δ = $\left |\begin{array}{r}                           
2    &{    -3    }    &{    5    }    \\
6    &{    0    }    &{    4    }    \\
1    &{    5    }    &{    7    }    \\
\end{array}\right | $.
2. By interchanging rows and columns, we get:
Δ1 = $\left |\begin{array}{r}                           
2    &{    6    }    &{    1    }    \\
-3    &{   0    }    &{    5    }    \\
5    &{    4    }    &{    7    }    \\
\end{array}\right |$.
3. Let us evaluate Δ. We will expand along R2.


4. Let us evaluate Δ1. We will expand along R2.


5. Comparing the results in (3) and (4), we see that:
Δ = Δ1


In the next section, we will see Property II.

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